Added javadoc comments
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@@ -1,10 +1,10 @@
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//JavaClasses/src/main/java/mattrixwv/HexagonalNumberGenerator.java
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//Matthew Ellison
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// Created: 08-20-22
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//Modified: 04-13-23
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//Modified: 08-11-24
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//This class generates hexagonal numbers
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/*
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Copyright (C) 2023 Matthew Ellison
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Copyright (C) 2024 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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@@ -26,18 +26,48 @@ import java.util.Iterator;
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import java.util.NoSuchElementException;
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/**
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* A generator for hexagonal numbers, which implements the {@link Iterator} interface.
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*
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* <p>
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* Hexagonal numbers are figurate numbers that represent hexagons. The n-th hexagonal number is given by
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* the formula: H(n) = 2n^2 - n.
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* </p>
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*
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* <p>
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* This generator allows iteration over hexagonal numbers starting from the first.
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* </p>
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*/
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public class HexagonalNumberGenerator implements Iterator<Long>{
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/**
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* The number to generate the next hexagonal number from.
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*/
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protected long num;
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/**
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* Constructs a new HexagonalNumberGenerator starting from the first hexagonal number.
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*/
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public HexagonalNumberGenerator(){
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num = 1L;
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}
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/**
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* Checks if there is a next hexagonal number that can be generated without overflow.
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*
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* @return {@code true} if the next hexagonal number can be generated, {@code false} otherwise
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*/
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@Override
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public boolean hasNext(){
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return (2 * num * num) > num;
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}
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/**
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* Returns the next hexagonal number.
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*
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* @return the next hexagonal number
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* @throws NoSuchElementException if the next hexagonal number would cause overflow
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*/
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@Override
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public Long next(){
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//If the number will result in an overflow throw an exception
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@@ -52,6 +82,12 @@ public class HexagonalNumberGenerator implements Iterator<Long>{
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return hexNum;
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}
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/**
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* Checks if a given number is a hexagonal number.
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*
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* @param x the number to check
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* @return {@code true} if the number is hexagonal, {@code false} otherwise
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*/
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public static boolean isHexagonal(Long x){
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Long n = Math.round((Math.sqrt(1.0D + (8L * x)) + 1L) / 4L);
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return ((2L * n * n) - n) == x;
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