Files
ProjectEulerCPP/Source/Problem14.cpp

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3.0 KiB
C++

//ProjectEuler/C++/Source/Problem14.cpp
//Matthew Ellison
// Created: 09-29-18
//Modified: 07-14-19
/*
The following iterative sequence is defined for the set of positive integers:
n → n/2 (n is even)
n → 3n + 1 (n is odd)
Which starting number, under one million, produces the longest chain?
*/
//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/myClasses
/*
Copyright (C) 2019 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>.
*/
#include <cinttypes>
#include <string>
#include <sstream>
#include "Stopwatch.hpp"
#include "../Headers/Problem.hpp"
#include "../Headers/Problem14.hpp"
uint64_t Problem14::MAX_NUM = 1000000;
uint64_t Problem14::checkSeries(uint64_t num){
uint64_t length = 1; //Start at 1 because you need to count the starting number
//Follow the series, adding 1 for each step you take
while(num > 1){
if((num % 2) == 0){
num /= 2;
}
else{
num = (3 * num) + 1;
}
++length;
}
return length;
}
Problem14::Problem14() : Problem("Which starting number, under one million, produces the longest chain using the itterative sequence?"), maxLength(0), maxNum(0){
}
void Problem14::solve(){
//If the problem has already been solved do nothing and end the function
if(solved){
return;
}
//Start the timer
timer.start();
//Loop through all numbers less than 1000000 and check them agains the series
for(uint64_t currentNum = 1;currentNum < MAX_NUM;++currentNum){
uint64_t currentLength = checkSeries(currentNum);
//If the current number has a longer series than the max then the current becomes the max
if(currentLength > maxLength){
maxLength = currentLength;
maxNum = currentNum;
}
}
//Stop the timer
timer.stop();
//Throw a flag to show the problem is solved
solved = true;
}
std::string Problem14::getString() const{
//If the problem hasn't been solved throw an exception
if(!solved){
throw unsolved();
}
std::stringstream results;
results << "The number " << maxNum << " produced a chain of " << maxLength << " steps";
return results.str();
}
uint64_t Problem14::getLength() const{
//If the problem hasn't been solved throw an exception
if(!solved){
throw unsolved();
}
return maxLength;
}
uint64_t Problem14::getStartingNumber() const{
//If the problem hasn't been solved throw an exception
if(!solved){
throw unsolved();
}
return maxNum;
}