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Added solution for problem 33
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@@ -33,7 +33,7 @@ namespace ProjectEulerCS{
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{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
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{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
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10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
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10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
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20, 21, 22, 23, 24, 25, 26, 27, 28, 29,
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20, 21, 22, 23, 24, 25, 26, 27, 28, 29,
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30, 31, 32, 67};
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30, 31, 32, 33, 67};
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public static System.Collections.Generic.List<int> PROBLEM_NUMBERS{
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public static System.Collections.Generic.List<int> PROBLEM_NUMBERS{
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get { return _PROBLEM_NUMBERS; }
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get { return _PROBLEM_NUMBERS; }
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}
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}
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@@ -74,6 +74,7 @@ namespace ProjectEulerCS{
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case 30: problem = new Problem30(); break;
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case 30: problem = new Problem30(); break;
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case 31: problem = new Problem31(); break;
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case 31: problem = new Problem31(); break;
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case 32: problem = new Problem32(); break;
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case 32: problem = new Problem32(); break;
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case 33: problem = new Problem33(); break;
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case 67: problem = new Problem67(); break;
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case 67: problem = new Problem67(); break;
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}
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}
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return problem;
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return problem;
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155
ProjectEulerCS/Problems/Problem33.cs
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155
ProjectEulerCS/Problems/Problem33.cs
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@@ -0,0 +1,155 @@
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//ProjectEuler/ProjectEulerCS/src/Problems/Problem33.cs
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//Matthew Ellison
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// Created: 02-06-21
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//Modified: 02-07-21
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/*
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The fraction 49/98 is a curious fraction, as an inexperienced mathematician in attempting to simplify it may incorrectly believe that 49/98 = 4/8, which is correct, is obtained by cancelling the 9s
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We shall consider fractions like, 30/50 = 3/5, to be trivial examples
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There are exactly four non-trivial examples of this type of fraction, less than one in value, and containing two digits in the numerator and denominator
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If the product of these four fractions is given in its lowest common terms, find the value of the denominator
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*/
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//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/CSClasses
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/*
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Copyright (C) 2021 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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*/
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using System;
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using System.Collections.Generic;
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namespace ProjectEulerCS.Problems{
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public class Problem33 : Problem{
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//Variables
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//Static variables
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private static readonly int MIN_NUMERATOR = 10; //The lowest the numerator can be
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private static readonly int MAX_NUMERATOR = 98; //The highest the numerator can be
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private static readonly int MIN_DENOMINATOR = 11; //The lowest the denominator can be
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private static readonly int MAX_DENOMINATOR = 99; //The highest the denominator can be
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//Instance variables
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private readonly List<int> numerators; //Holds the numerators that were found
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private readonly List<int> denominators; //Holds the denominators that were found
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private int prodDenominator; //Holds the answer to question
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//Gets
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//The results of the problem
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public override string Result{
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get{
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if(!solved){
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throw new Unsolved();
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}
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return $"The denominator of the product is {prodDenominator}";
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}
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}
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public List<int> Numerators{
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get{
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if(!solved){
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throw new Unsolved();
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}
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return numerators;
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}
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}
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public List<int> Denominators{
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get{
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if(!solved){
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throw new Unsolved();
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}
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return denominators;
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}
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}
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//Functions
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//Constructor
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public Problem33() : base("If the product of these four fractions is given in its lowest common terms, find the value of the denominator"){
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numerators = new List<int>();
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denominators = new List<int>();
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prodDenominator = 1;
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}
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//Operational functions
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//Solve the problem
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public override void Solve(){
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//If the problem has already been solved do nothing and end the function
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if (solved){
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return;
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}
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//Start the timer
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timer.Start();
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//Search every possible numerator/denominator pair
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for(int denominator = MIN_DENOMINATOR;denominator <= MAX_DENOMINATOR;++denominator){
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for(int numerator = MIN_NUMERATOR;(numerator < denominator) &&(numerator <= MAX_NUMERATOR);++numerator){
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string denom = denominator.ToString();
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string num = numerator.ToString();
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int tempNum = 0;
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int tempDenom = 1;
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//Check that this isn't a trivial example
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if((num[1] == '0') && (denom[1] == '0')){
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continue;
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}
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//Remove the offending digits if they exist
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else if(num[0] == denom[0]){
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tempNum = num[1] - 48;
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tempDenom = denom[1] - 48;
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}
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else if(num[0] == denom[1]){
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tempNum = num[1] - 48;
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tempDenom = denom[0] - 48;
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}
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else if(num[1] == denom[0]){
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tempNum = num[0] - 48;
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tempDenom = denom[1] - 48;
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}
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else if(num[1] == denom[1]){
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tempNum = num[0] - 48;
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tempDenom = denom[0] - 48;
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}
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//Test if the new fraction is the same as the old one
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if(((double)tempNum / tempDenom) == ((double)numerator / denominator)){
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numerators.Add(numerator);
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denominators.Add(denominator);
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}
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}
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}
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//Get the product of the numbers
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int numProd = mee.Algorithms.GetProd(numerators);
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int denomProd = mee.Algorithms.GetProd(denominators);
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//Get the gcd to reduce to lowest terms
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int gcd = mee.Algorithms.GCD(numProd, denomProd);
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//Save the denominator
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prodDenominator = denomProd / gcd;
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//Stop the timer
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timer.Stop();
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//Thow a flag to show the problem is solved
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solved = true;
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}
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//Reset the problem so it can be run again
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public override void Reset(){
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base.Reset();
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numerators.Clear();
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denominators.Clear();
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}
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}
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}
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/* Results:
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The denominator of the product is 100
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It took an average of 221.559 microseconds to run this problem through 100 iterations
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*/
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