Added solution to problem 5

ProjectEulerCS/Benchmark.cs

@@ -27,7 +27,8 @@ using System.Collections.Generic;
 namespace ProjectEulerCS{
 	public class Benchmark{
 		private enum BenchmarkOptions { runSpecific = 1, runAllShort, runAll, exit, size };
-		private static readonly List<int> tooLong = new List<int>();
+		private static readonly List<int> tooLong = new List<int>()
+				{5};
 
 		//The driver function for the benchmark selection
 		public static void benchmarkMenu(){

ProjectEulerCS/ProblemSelection.cs

@@ -28,7 +28,7 @@ namespace ProjectEulerCS{
 	public class ProblemSelection{
 		//Holds the valid problem numbers
 		private static readonly List<int> _PROBLEM_NUMBERS = new List<int>()
-				{0, 1, 2, 3, 4};
+				{0, 1, 2, 3, 4, 5};
 		public static System.Collections.Generic.List<int> PROBLEM_NUMBERS{
 			get { return _PROBLEM_NUMBERS; }
 		}
@@ -41,6 +41,7 @@ namespace ProjectEulerCS{
 				case 2: problem = new Problem2(); break;
 				case 3: problem = new Problem3(); break;
 				case 4: problem = new Problem4(); break;
+				case 5: problem = new Problem5(); break;
 			}
 			return problem;
 		}

ProjectEulerCS/Problems/Problem5.cs

@@ -0,0 +1,97 @@
+//ProjectEuler/ProjectEulerCS/src/Problems/Problem5.cs
+//Matthew Ellison
+// Created: 08-23-20
+//Modified: 08-23-20
+//What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
+//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/CSClasses
+/*
+	Copyright (C) 2020  Matthew Ellison
+
+	This program is free software: you can redistribute it and/or modify
+	it under the terms of the GNU Lesser General Public License as published by
+	the Free Software Foundation, either version 3 of the License, or
+	(at your option) any later version.
+
+	This program is distributed in the hope that it will be useful,
+	but WITHOUT ANY WARRANTY; without even the implied warranty of
+	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+	GNU Lesser General Public License for more details.
+
+	You should have received a copy of the GNU Lesser General Public License
+	along with this program.  If not, see <https://www.gnu.org/licenses/>.
+*/
+
+
+namespace ProjectEulerCS{
+	public class Problem5 : Problem{
+		//Variables
+		//Instance variables
+		private int smallestNum;	//The smallest number that is found
+		public int number{
+			get{
+				if(!solved){
+					throw new Unsolved();
+				}
+				return smallestNum;
+			}
+		}
+
+		//Functions
+		//Constructor
+		public Problem5() : base("What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?"){
+			smallestNum = 0;
+		}
+		//Operational functions
+		//Solve the problem
+		public override void solve(){
+			//If the problem has already been solved do nothing and end the function
+			if(solved){
+				return;
+			}
+
+			//Start the timer
+			_timer.start();
+
+			//Start at 20 because it must at least be divisible by 20. Increment by 2 because it must be an even number to be divisible by 2
+			bool numFound = false;	//A flag for finding the divisible number
+			int currentNum = 20;	//The number that it are currently checking against
+			while((currentNum > 0) && (!numFound)){
+				//Start by assuming you found the number (because we throw a flag if we didn't find it)
+				numFound = true;
+				//Step through every number from 1-20 seeing if the current number is divisible by it
+				for(int divisor = 1;divisor <= 20;++divisor){
+					//If it is not divisible then throw a flag and start looking at the next number
+					if((currentNum % divisor) != 0){
+						numFound = false;
+						break;
+					}
+				}
+				//If you didn't find the correct number then increment by 2
+				if(!numFound){
+					currentNum += 2;
+				}
+			}
+
+			smallestNum = currentNum;
+
+			//Stop the timer
+			_timer.stop();
+
+			//Throw a flag to show the problem is solved
+			solved = true;
+
+			//Save the results
+			_result = "The smallest positive number evenly divisible by all numbers 1-20 is " + currentNum;
+		}
+		//Reset the problem so it can be run again
+		public override void reset(){
+			base.reset();
+			smallestNum = 0;
+		}
+	}
+}
+
+/* Results:
+The smallest positive number evenly divisible by all numbers 1-20 is 232792560
+It took an average of 2.549 seconds to run this problem through 100 iterations
+*/