Added solution to problem 14

ProjectEulerCS/ProblemSelection.cs

@@ -31,7 +31,7 @@ namespace ProjectEulerCS{
 		//Holds the valid problem numbers
 		private static readonly List<int> _PROBLEM_NUMBERS = new List<int>()
 				{ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9,
-				 10, 11, 12, 13};
+				 10, 11, 12, 13, 14};
 		public static System.Collections.Generic.List<int> PROBLEM_NUMBERS{
 			get { return _PROBLEM_NUMBERS; }
 		}
@@ -53,6 +53,7 @@ namespace ProjectEulerCS{
 				case 11: problem = new Problem11(); break;
 				case 12: problem = new Problem12(); break;
 				case 13: problem = new Problem13(); break;
+				case 14: problem = new Problem14(); break;
 			}
 			return problem;
 		}

ProjectEulerCS/Problems/Problem13.cs

@@ -1,4 +1,4 @@
-//ProjectEuler/ProjectEulerCS/src/Problems/Problem12.cs
+//ProjectEuler/ProjectEulerCS/src/Problems/Problem13.cs
 //Matthew Ellison
 // Created: 08-24-20
 //Modified: 08-24-20

ProjectEulerCS/Problems/Problem14.cs

@@ -0,0 +1,121 @@
+//ProjectEuler/ProjectEulerCS/src/Problems/Problem14.cs
+//Matthew Ellison
+// Created: 08-24-20
+//Modified: 08-24-20
+/*
+The following iterative sequence is defined for the set of positive integers:
+n → n/2 (n is even)
+n → 3n + 1 (n is odd)
+Which starting number, under one million, produces the longest chain?
+*/
+//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/CSClasses
+/*
+	Copyright (C) 2020  Matthew Ellison
+
+	This program is free software: you can redistribute it and/or modify
+	it under the terms of the GNU Lesser General Public License as published by
+	the Free Software Foundation, either version 3 of the License, or
+	(at your option) any later version.
+
+	This program is distributed in the hope that it will be useful,
+	but WITHOUT ANY WARRANTY; without even the implied warranty of
+	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+	GNU Lesser General Public License for more details.
+
+	You should have received a copy of the GNU Lesser General Public License
+	along with this program.  If not, see <https://www.gnu.org/licenses/>.
+*/
+
+
+namespace ProjectEulerCS.Problems{
+	public class Problem14 : Problem{
+		//Variables
+		//Static variables
+		private const long MAX_NUM = 1000000 - 1;	//This is the top number that you will be checking against the series
+		//Instance variables
+		private long maxLength;	//This is the length of the longest chain
+		public long Length{
+			get{
+				if(!solved){
+					throw new Unsolved();
+				}
+				return maxLength;
+			}
+		}
+		private long maxNum;	//This is the starting number of the longest chain
+		public long StartingNumber{
+			get{
+				if(!solved){
+					throw new Unsolved();
+				}
+				return maxNum;
+			}
+		}
+
+		//Functions
+		//Constructor
+		public Problem14() : base("Which starting number, under one million, produces the longest chain using the itterative sequence?"){
+			maxLength = 0;
+			maxNum = 0;
+		}
+		//Operational functions
+		//Solve the problem
+		public override void Solve(){
+			//If the problem has already been solved do nothing and end the function
+			if(solved){
+				return;
+			}
+
+			//Start the timer
+			_timer.Start();
+
+			//Loop through all numbers <= MAX_NUM and check them against the series
+			for(long currentNum = 1;currentNum <= MAX_NUM;++currentNum){
+				long currentLength = CheckSeries(currentNum);
+				//If the current number has a longer series than the max then the current becomes the max
+				if(currentLength > maxLength){
+					maxLength = currentLength;
+					maxNum = currentNum;
+				}
+			}
+
+			//Stop the timer
+			_timer.Stop();
+
+			//Throw a flag to show the problem is solved
+			solved = true;
+
+			//Save the results
+			_result = "The number " + maxNum + " produced a chain of " + maxLength + " steps";
+		}
+		//This function follows the rules of the sequence and returns its length
+		private long CheckSeries(long num){
+			long length = 1;	//Start at 1 because you need to count the starting number
+
+			//Follow the series, adding 1 for each time you take
+			while(num > 1){
+				if((num % 2) == 0){
+					num /= 2;
+				}
+				else{
+					num = (3 * num) + 1;
+				}
+				++length;
+			}
+
+			//Return the length of the series
+			return length;
+		}
+		//Reset the problem so it can be run again
+		public override void Reset(){
+			base.Reset();
+			maxLength = 0;
+			maxNum = 0;
+		}
+	}
+}
+
+/* Results:
+The number 837799 produced a chain of 525 steps
+It took an average of 249.883 milliseconds to run this problem through 100 iterations
+*/