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Updated for performance
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@@ -1,11 +1,11 @@
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//ProjectEuler/Java/Problem26.java
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//ProjectEulerJava/src/main/java/mattrixwv/ProjectEuler/Problems/Problem26.java
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//Matthew Ellison
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//Matthew Ellison
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// Created: 07-28-19
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// Created: 07-28-19
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//Modified: 07-28-19
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//Modified: 06-17-20
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//What is the index of the first term in the Fibonacci sequence to contain 1000 digits?
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//Find the value of d < 1000 for which 1/d contains the longest recurring cycle in its decimal fraction part.
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//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/JavaClasses
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//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/JavaClasses
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/*
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/*
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Copyright (C) 2019 Matthew Ellison
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Copyright (C) 2020 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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it under the terms of the GNU Lesser General Public License as published by
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@@ -30,33 +30,33 @@ import java.util.ArrayList;
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public class Problem26 extends Problem{
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public class Problem26 extends Problem{
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//The number of digits needed in the number
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//The number of digits needed in the number
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private static final Integer TOP_NUM = 999;
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private static final int TOP_NUM = 999;
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public Problem26(){
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public Problem26(){
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super("What is the index of the first term in the Fibonacci sequence to contain 1000 digits?");
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super("Find the value of d < 1000 for which 1/d contains the longest recurring cycle in its decimal fraction part.");
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}
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}
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public void solve(){
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public void solve(){
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//The length of the longest cycle
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//The length of the longest cycle
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Integer longestCycle = 0;
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int longestCycle = 0;
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//The starting denominator of the longest cycle
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//The starting denominator of the longest cycle
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Integer longestNumber = 0;
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int longestNumber = 0;
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//Start the timer
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//Start the timer
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timer.start();
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timer.start();
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//Start with 1/2 and find out how long the longest cycle is by checking the remainders
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//Start with 1/2 and find out how long the longest cycle is by checking the remainders
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//Loop through every number from 2-999 and use it for the denominator
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//Loop through every number from 2-999 and use it for the denominator
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for(Integer denominator = 2;denominator <= TOP_NUM;++denominator){
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for(int denominator = 2;denominator <= TOP_NUM;++denominator){
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ArrayList<Integer> denomList = new ArrayList<Integer>();
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ArrayList<Integer> denomList = new ArrayList<Integer>();
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Boolean endFound = false; //Holds whether we have found an end to the number (either a cycle or a 0 for remainder)
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boolean endFound = false; //Holds whether we have found an end to the number (either a cycle or a 0 for remainder)
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Boolean cycleFound = false; //Holds whether a cycle was detected
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boolean cycleFound = false; //Holds whether a cycle was detected
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Integer numerator = 1; //The numberator that will be divided. Always starts at 1
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int numerator = 1; //The numerator that will be divided. Always starts at 1
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while(!endFound){
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while(!endFound){
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//Get the remainder after the division
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//Get the remainder after the division
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Integer remainder = numerator % denominator;
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int remainder = numerator % denominator;
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//Check if the remainder is 0
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//Check if the remainder is 0
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//If it is set the flag
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//If it is set the flag
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if(remainder.equals(0)){
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if(remainder == 0){
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endFound = true;
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endFound = true;
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}
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}
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//Check if the remainder is in the list
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//Check if the remainder is in the list
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@@ -85,7 +85,7 @@ public class Problem26 extends Problem{
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//Stop the timer
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//Stop the timer
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timer.stop();
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timer.stop();
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//Save the restuls
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//Save the results
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result = String.format("The longest cycle is %d digits long\nIt started with the number %d\n", longestCycle, longestNumber);
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result = String.format("The longest cycle is %d digits long\nIt started with the number %d\n", longestCycle, longestNumber);
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}
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}
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}
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}
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@@ -93,5 +93,5 @@ public class Problem26 extends Problem{
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/* Results:
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/* Results:
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The longest cycle is 982 digits long
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The longest cycle is 982 digits long
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It started with the number 983
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It started with the number 983
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It took 28.969 milliseconds to solve this problem.
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It took 10.429 milliseconds to solve this problem.
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*/
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*/
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