ProjectEuler/ProjectEulerJava
1
0
Fork 0
mirror of https://bitbucket.org/Mattrixwv/projecteulerjava.git synced 2025-12-06 17:13:58 -05:00
Code Issues Packages Projects Releases Wiki Activity

Updated for performance

Browse Source
This commit is contained in:
Mattrixwv
2020-06-17 18:42:28 -04:00
parent 465b6165c0
commit 86b10bae89
1 changed files with 16 additions and 16 deletions
Download Patch File Download Diff File Expand all files Collapse all files

32
src/main/java/mattrixwv/ProjectEuler/Problems/Problem26.java
View File

@@ -1,11 +1,11 @@
//ProjectEuler/Java/Problem26.java
//ProjectEulerJava/src/main/java/mattrixwv/ProjectEuler/Problems/Problem26.java
//Matthew Ellison
// Created: 07-28-19
//Modified: 07-28-19
//What is the index of the first term in the Fibonacci sequence to contain 1000 digits?
//Modified: 06-17-20
//Find the value of d < 1000 for which 1/d contains the longest recurring cycle in its decimal fraction part.
//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/JavaClasses
/*
Copyright (C) 2019 Matthew Ellison
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
@@ -30,33 +30,33 @@ import java.util.ArrayList;
public class Problem26 extends Problem{
//The number of digits needed in the number
private static final Integer TOP_NUM = 999;
private static final int TOP_NUM = 999;
public Problem26(){
super("What is the index of the first term in the Fibonacci sequence to contain 1000 digits?");
super("Find the value of d < 1000 for which 1/d contains the longest recurring cycle in its decimal fraction part.");
}
public void solve(){
//The length of the longest cycle
Integer longestCycle = 0;
int longestCycle = 0;
//The starting denominator of the longest cycle
Integer longestNumber = 0;
int longestNumber = 0;
//Start the timer
timer.start();
//Start with 1/2 and find out how long the longest cycle is by checking the remainders
//Loop through every number from 2-999 and use it for the denominator
for(Integer denominator = 2;denominator <= TOP_NUM;++denominator){
for(int denominator = 2;denominator <= TOP_NUM;++denominator){
ArrayList<Integer> denomList = new ArrayList<Integer>();
Boolean endFound = false; //Holds whether we have found an end to the number (either a cycle or a 0 for remainder)
Boolean cycleFound = false; //Holds whether a cycle was detected
Integer numerator = 1; //The numberator that will be divided. Always starts at 1
boolean endFound = false; //Holds whether we have found an end to the number (either a cycle or a 0 for remainder)
boolean cycleFound = false; //Holds whether a cycle was detected
int numerator = 1; //The numerator that will be divided. Always starts at 1
while(!endFound){
//Get the remainder after the division
Integer remainder = numerator % denominator;
int remainder = numerator % denominator;
//Check if the remainder is 0
//If it is set the flag
if(remainder.equals(0)){
if(remainder == 0){
endFound = true;
}
//Check if the remainder is in the list
@@ -85,7 +85,7 @@ public class Problem26 extends Problem{
//Stop the timer
timer.stop();
//Save the restuls
//Save the results
result = String.format("The longest cycle is %d digits long\nIt started with the number %d\n", longestCycle, longestNumber);
}
}
@@ -93,5 +93,5 @@ public class Problem26 extends Problem{
/* Results:
The longest cycle is 982 digits long
It started with the number 983
It took 28.969 milliseconds to solve this problem.
It took 10.429 milliseconds to solve this problem.
*/