//ProjectEulerJava/src/main/java/mattrixwv/ProjectEuler/Problems/Problem9.java //Matthew Ellison // Created: 03-02-19 //Modified: 06-27-23 //There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc. //Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/JavaClasses /* Copyright (C) 2023 Matthew Ellison This program is free software: you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License for more details. You should have received a copy of the GNU Lesser General Public License along with this program. If not, see . */ package com.mattrixwv.project_euler.problems; import com.mattrixwv.project_euler.exceptions.Unsolved; public class Problem9 extends Problem{ //Variables //Static variables protected int GOAL_SUM = 1000; //The number that we want the sum of a, b, and c to equal //Instance variables protected int a; //The size of the first side protected int b; //The size of the second side protected double c; //The size of the hyp protected boolean found; //A flag to determine if we have found the solution yet //Functions //Constructor public Problem9(){ super(String.format("There exists exactly one Pythagorean triplet for which a + b + c = %d. Find the product abc.", 1000)); a = 1; b = 0; c = 0; found = false; } //Operational functions //Solve the problem @Override public void solve(){ //If the problem has already been solved do nothing and end the function if(solved){ return; } //Start the timer timer.start(); //Loop through all possible a's while((a < GOAL_SUM) && !found){ b = a + 1; //b must be larger than a c = Math.sqrt((a * a) + (double)(b * b)); //Compute the hyp //Loop through all possible b's for this a while((a + b + c) < GOAL_SUM){ ++b; c = Math.sqrt((a * a) + (double)(b * b)); } //If the sum == 1000 you found the number, otherwise go to the next possible a if((a + b + c) == GOAL_SUM){ found = true; } else{ ++a; } } //Stop the timer timer.stop(); //Throw a flag to show the problem is solved if(found){ solved = true; } else{ throw new Unsolved("The problem was not solved!"); } } //Reset the problem so it can be run again @Override public void reset(){ super.reset(); a = 1; b = 0; c = 0; found = false; } //Gets //Returns the result of solving the problem @Override public String getResult(){ solvedCheck("result"); return String.format("The Pythagorean triplet is %d + %d + %d%nThe numbers' product is %d", a, b, Math.round(c), a * b * Math.round(c)); } //Returns the length of the first side public int getSideA(){ solvedCheck("first side"); return a; } //Returns the length of the second side public int getSideB(){ solvedCheck("second side"); return b; } //Returns the length of the hyp public int getSideC(){ solvedCheck("third side"); return (int)c; } //Returns the product of the 3 sides public int getProduct(){ solvedCheck("product of all three sides"); return a * b * (int)c; } } /* Results: The Pythagorean triplet is 200 + 375 + 425 The numbers' product is 31875000 It took an average of 380.920 microseconds to run this problem through 100 iterations */