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Updated problems to be more in line with conventions

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Mattrixwv
2020-06-19 19:58:36 -04:00
parent 1bfd097fa3
commit 7d107c1071
31 changed files with 174 additions and 182 deletions
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65
Problem19.lua
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@@ -1,7 +1,7 @@
--ProjectEuler/lua/Problem19.lua
--Matthew Ellison
-- Created: 03-13-19
--Modified: 03-28-19
--Modified: 06-19-20
--How many Sundays fell on the first of the month during the twentieth century (1 Jan 1901 to 31 Dec 2000)?
--[[
You are given the following information, but you may prefer to do some research for yourself.
@@ -16,7 +16,7 @@ A leap year occurs on any year evenly divisible by 4, but not on a century unles
]]
--All of my requires, unless otherwise listed, can be found at https://bitbucket.org/Mattrixwv/luaClasses
--[[
Copyright (C) 2019 Matthew Ellison
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
@@ -48,20 +48,41 @@ DAYS = {
ERROR = 8;
}
START_YEAR = 1901;
END_YEAR = 2000;
local START_YEAR = 1901;
local END_YEAR = 2000;
local function isLeapYear(year)
local answer;
if(year < 1) then
answer = false;
elseif((year % 100) == 0) then
--This rule only applies at and after 1800
if(year <= 1700) then
answer = true;
elseif((year % 400) == 0) then
answer = true;
else
answer = false;
end
elseif((year % 4) == 0) then
answer = true;
else
answer = false;
end
return answer;
end
--Return the day of the week that the date you pass into it is on
function getDay(month, day, year)
local function getDay(month, day, year)
--Make sure the numbers are within propper bounds
if((month < 1) or (month > 12) or (day < 1) or (day > 31) or (year < 1)) then
return DAYS.ERROR;
end
numDays = 0;
currentYear = 1;
currentMonth = 1;
currentDay = DAYS.SATURDAY;
local numDays = 0;
local currentYear = 1;
local currentMonth = 1;
local currentDay = DAYS.SATURDAY;
day = day - 1;
--Add the correct number of days for every year
@@ -132,29 +153,9 @@ function getDay(month, day, year)
return day;
end
function isLeapYear(year)
if(year < 1) then
answer = false;
elseif((year % 100) == 0) then
--This rule only applies at and after 1800
if(year <= 1700) then
answer = true;
elseif((year % 400) == 0) then
answer = true;
else
answer = false;
end
elseif((year % 4) == 0) then
answer = true;
else
answer = false;
end
return answer;
end
--Setup the variables
timer = Stopwatch:create();
totalSundays = 0;
local timer = Stopwatch:create();
local totalSundays = 0;
--Start the timer
timer:start();
@@ -163,7 +164,7 @@ timer:start();
for year=START_YEAR,END_YEAR do
--Run for all months in the year
for month=1,12 do
day = getDay(month, 1, year);
local day = getDay(month, 1, year);
if(day == DAYS.ERROR) then
io.output("There was an error with the day\n");
os.exit();