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ProjectEulerLua/Problem19.lua

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Lua

--ProjectEuler/lua/Problem19.lua
--Matthew Ellison
-- Created: 03-13-19
--Modified: 06-19-20
--How many Sundays fell on the first of the month during the twentieth century (1 Jan 1901 to 31 Dec 2000)?
--[[
You are given the following information, but you may prefer to do some research for yourself.
1 Jan 1900 was a Monday.
Thirty days has September,
April, June and November.
All the rest have thirty-one,
Saving February alone,
Which has twenty-eight, rain or shine.
And on leap years, twenty-nine.
A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
]]
--All of my requires, unless otherwise listed, can be found at https://bitbucket.org/Mattrixwv/luaClasses
--[[
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>.
]]
require "Stopwatch"
DAYS = {
SUNDAY = 0,
MONDAY = 1,
TUESDAY = 2,
WEDNESDAY = 3,
THURSDAY = 4,
FRIDAY = 5,
SATURDAY = 6,
NUMBER_OF_DAYS = 7,
ERROR = 8;
}
local START_YEAR = 1901;
local END_YEAR = 2000;
local function isLeapYear(year)
local answer;
if(year < 1) then
answer = false;
elseif((year % 100) == 0) then
--This rule only applies at and after 1800
if(year <= 1700) then
answer = true;
elseif((year % 400) == 0) then
answer = true;
else
answer = false;
end
elseif((year % 4) == 0) then
answer = true;
else
answer = false;
end
return answer;
end
--Return the day of the week that the date you pass into it is on
local function getDay(month, day, year)
--Make sure the numbers are within propper bounds
if((month < 1) or (month > 12) or (day < 1) or (day > 31) or (year < 1)) then
return DAYS.ERROR;
end
local numDays = 0;
local currentYear = 1;
local currentMonth = 1;
local currentDay = DAYS.SATURDAY;
day = day - 1;
--Add the correct number of days for every year
while(currentYear < year) do
if(isLeapYear(currentYear)) then
numDays = numDays + 366;
else
numDays = numDays + 365;
end
currentYear = currentYear + 1;
end
--Add the correct number of days for every month
while(currentMonth < month) do
--February
if(currentMonth == 2) then
if(isLeapYear(currentYear)) then
numDays = numDays + 29;
else
numDays = numDays + 28;
end
--31 day months
elseif((currentMonth == 1) or (currentMonth == 3) or (currentMonth == 5) or (currentMonth == 7) or (currentMonth == 8) or (currentMonth == 10) or (currentMonth == 12)) then
numDays = numDays + 31;
--30 day months
else
numDays = numDays + 30;
end
currentMonth = currentMonth + 1;
end
--Account for the weird year of 1752
if(year > 1752) then
numDays = numDays - 11;
elseif(year == 1752) then
if(month > 9) then
numDays = numDays - 11;
elseif(month == 9) then
if(day >= 14) then
numDays = numDays - 11;
--Days 3-13 were skipped that year
elseif((day > 2) and (day < 14)) then
return DAYS.ERROR;
end
end
end
--Add the correct number of days for every day
numDays = numDays + day;
currentDay = currentDay + numDays;
currentDay = currentDay % DAYS.NUMBER_OF_DAYS;
if(currentDay == DAYS.SUNDAY) then
day = DAYS.SUNDAY;
elseif(currentDay == DAYS.MONDAY) then
day = DAYS.MONDAY;
elseif(currentDay == DAYS.TUESDAY) then
day = DAYS.TUESDAY;
elseif(currentDay == DAYS.WEDNESDAY) then
day = DAYS.WEDNESDAY;
elseif(currentDay == DAYS.THURSDAY) then
day = DAYS.THURSDAY;
elseif(currentDay == DAYS.FRIDAY) then
day = DAYS.FRIDAY;
elseif(currentDay == DAYS.SATURDAY) then
day = DAYS.SATURDAY;
else
day = DAYS.ERROR;
end
--Return the day generated
return day;
end
--Setup the variables
local timer = Stopwatch:create();
local totalSundays = 0;
--Start the timer
timer:start();
--Run for all years up to 2000
for year=START_YEAR,END_YEAR do
--Run for all months in the year
for month=1,12 do
local day = getDay(month, 1, year);
if(day == DAYS.ERROR) then
io.output("There was an error with the day\n");
os.exit();
elseif(day == DAYS.SUNDAY) then
totalSundays = totalSundays + 1;
end
end
end
--Stop the timer
timer:stop()
--Print the results
io.write("There are " .. totalSundays .. " Sundays that landed on the first of the months from " .. START_YEAR .. " to " .. END_YEAR .. '\n');
io.write("It took " .. timer:getMilliseconds() .. " milliseconds to run this algorithm\n");
--[[ Results:
There are 171 Sundays that landed on the first of the months from 1901 to 2000
It took 390.0 milliseconds to run this algorithm
]]