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90 lines
3.2 KiB
Lua
90 lines
3.2 KiB
Lua
--ProjectEuler/lua/Problem30.lua
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-- Created: 10-28-19
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--Modified: 06-19-20
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--Find the sum of all the numbers that can be written as the sum of the fifth powers of their digits.
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--All of my requires, unless otherwise listed, can be found at https://bitbucket.org/Mattrixwv/luaClasses
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--[[
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Copyright (C) 2020 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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]]
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require "Stopwatch"
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--Returns a table with the individual digits of the number passed to it
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local function getDigits(num)
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local listOfDigits = {}; --This table holds the individual digits of num
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--The easiest way to get the individual digits of a number is by converting it to a string
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local digits = tostring(num);
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--Start with the first digit, convert it to an integer, store it in the table, and move to the next digit
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for cnt = 1, #digits do
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table.insert(listOfDigits, tonumber(string.sub(digits, cnt, cnt)));
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end
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--Return the table of digits
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return listOfDigits;
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end
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--Gets the sum of a table of numbers
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local function getSumOfTable(ary)
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local sum = 0; --Start the sum at 0 so you can add to it
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--Add every number in the table to the sum
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for cnt = 1, #ary do
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sum = sum + ary[cnt];
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end
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--Return the sum
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return sum;
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end
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--Setup the variables
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local timer = Stopwatch:create();
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local TOP_NUM = 1000000; --This is the largest number that will be checked
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local BOTTOM_NUM = 2; --Starts with 2 because 0 and 1 don't count
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local POWER_RAISED = 5; --This is the power that the digits are raised to
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local sumOfFifthNumbers = {}; --This is a table of the numbers that are the sum of the fifth power of their digits
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--Start the timer
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timer:start();
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--Start with the lowest number and increment until you reach the largest number
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for currentNum = BOTTOM_NUM, TOP_NUM do
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--Get the digits of the number
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local digits = getDigits(currentNum);
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--Get the sum of the powers
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local sumOfPowers = 0;
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for cnt = 1, #digits do
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sumOfPowers = sumOfPowers + math.pow(digits[cnt], POWER_RAISED);
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end
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--Check if the sum of the powers is the same as the number
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--If it is add it to the list, otherwise continue to the next number
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if(sumOfPowers == currentNum) then
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table.insert(sumOfFifthNumbers, currentNum);
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end
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end
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--Stop the timer
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timer:stop();
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--Print the results
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io.write("The sum of all the numbers that can be written as the sum of the fifth powers of their digits is " .. getSumOfTable(sumOfFifthNumbers) .. '\n');
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io.write("It took " .. timer:getString() .. " to run this algorithm\n");
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--[[ Results:
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The sum of all the numbers that can be written as the sum of the fifth powers of their digits is 443839
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It took 2.706 seconds to run this algorithm
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]]
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