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Problem15.m
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78
Problem15.m
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function numOfRoutes = Problem15()
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%ProjectEuler/Octave/Problem15.m
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%Matthew Ellison
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% Created:
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%Modified: 03-28-19
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%How many routes from the top left corner to the bottom right corner are there through a 20×20 grid if you can only move right and down?
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%{
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Copyright (C) 2019 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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%}
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%Setup your variables
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gridLength = 20;
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gridHeight = 20;
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numOfRoutes = 0;
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currentX = 0;
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currentY = 0;
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%Start the timer
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startTime = clock();
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%Get the number of routes from top left to bottom right
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numOfRoutes = movement(currentX, currentY, gridLength, gridHeight);
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%Stop the timer
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endTime = clock();
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%Print the results
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printf("The number of routes from top left to bottom right is %d\n", numOfRoutes)
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printf("It took %f seconds to run this algorithm\n", etime(endTime, startTime))
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%Cleanup your variables
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clear gridLength;
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clear gridHeight;
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clear numOfRoutes;
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clear currentX;
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clear currentY;
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clear startTime;
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clear endTime;
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end %End of Problem15()
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%Simulates moving along the grid
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%Recurses moving right first, then down
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function num = movement(currentX, currentY, gridLength, gridHeight)
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num = 0;
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%See if it is at the end of the grid
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if((currentX == gridLength) && (currentY == gridHeight))
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num = 1;
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else
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%If it's not move right first, then move down, if possible
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if(currentX < gridLength)
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num += movement(currentX + 1, currentY, gridLength, gridHeight);
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end
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if(currentY < gridHeight)
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num += movement(currentX, currentY + 1, gridLength, gridHeight);
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end
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end
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end
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%{
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Results:
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///This follows the same idea as my cpp program but I got tired of waiting for it to finish after two hours.
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///It should work, but is still untested
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%}
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