Initial commit with existing files

Problem5.m

@@ -0,0 +1,79 @@
+%ProjectEuler/Octave/Problem5.m
+%Matthew Ellison
+% Created: 03-16-19
+%Modified: 03-28-19
+%What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
+%{
+	Copyright (C) 2019  Matthew Ellison
+
+	This program is free software: you can redistribute it and/or modify
+	it under the terms of the GNU Lesser General Public License as published by
+	the Free Software Foundation, either version 3 of the License, or
+	(at your option) any later version.
+
+	This program is distributed in the hope that it will be useful,
+	but WITHOUT ANY WARRANTY; without even the implied warranty of
+	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+	GNU Lesser General Public License for more details.
+
+	You should have received a copy of the GNU Lesser General Public License
+	along with this program.  If not, see <https://www.gnu.org/licenses/>.
+%}
+
+
+%Create your variables
+nums = [1:20];
+factors = [1];	%The factors that are already in the number
+list = [];	%For a temperary list of the factors of the current number
+counter = 1;
+
+%Start the timer
+startTime = clock();
+
+%You need to find the factors of all the numbers from 1->20
+while(counter <= size(nums)(2))
+	list = factor(nums(counter));
+
+	%Search factors and try to match all elements in list
+	listCnt = 1;
+	factorCnt = 1;
+	while(listCnt <= size(list)(2))
+		if((factorCnt > size(factors)(2)) || (factors(factorCnt) > list(listCnt)))
+			%If it was not found add the factor to the list for the number and reset the counters
+			factors(end + 1) = list(listCnt);
+			factors = sort(factors);
+			factorCnt = 1;
+			listCnt = 1;
+		elseif(factors(factorCnt) == list(listCnt))
+			++listCnt;
+			++factorCnt;
+		else
+			++factorCnt;
+		end
+	end
+	++counter;
+end
+
+%Stop the timer
+endTime = clock();
+
+%Print the results
+printf("The smallest positive number that is evenly divisible by all numbers 1-20 is %d\n", prod(factors))
+printf("It took %f seconds to run this algorithm\n", etime(endTime, startTime))
+
+%Cleanup your variables
+clear counter;
+clear factorCnt;
+clear listCnt;
+clear list;
+clear nums;
+clear factors;
+clear startTime;
+clear endTime;
+clear ans;
+
+%{
+Results:
+The smallest positive number that is evenly divisible by all numbers 1-20 is 232792560
+It took 0.010742 seconds to run this algorithm
+%}