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80 lines
2.8 KiB
Matlab
80 lines
2.8 KiB
Matlab
function [] = Problem30()
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%ProjectEuler/Octave/Problem30.m
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%Matthew Ellison
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% Created: 10-28-19
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%Modified: 10-28-19
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%Find the sum of all the numbers that can be written as the sum of the fifth powers of their digits.
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%{
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Copyright (C) 2019 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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%}
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%Setup the variables
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TOP_NUM = 1000000; %This is the largest number that will be check
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BOTTOM_NUM = 2; %Starts with 2 because 0 and 1 don't count
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POWER_RAISED = 5; %This is the power that the digits are raised to
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sumOfFifthNumbers = []; %This is an array of the numbers that are the sum of the fifth power of their digits
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sumOfArray = 0; %This is the sum of the sumOfFifthNumbers array
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%Start the timer
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startTime = clock();
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%Start with the lowest number and increment until you reach the largest number
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for currentNum = BOTTOM_NUM : TOP_NUM
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printf("%d\n", currentNum)
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%Get the digits of the number
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digits = getDigits(currentNum);
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%Get the sum of the powers
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sumOfPowers = 0;
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for cnt = 1 : size(digits)(2)
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sumOfPowers += digits(cnt)^POWER_RAISED;
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end
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%Check if the sum of the powers is the same as the number
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%If it is add it to the list, otherwise continue to the next number
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if(sumOfPowers == currentNum)
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sumOfFifthNumbers(end + 1) = currentNum;
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end
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end
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sumOfArray = sum(sumOfFifthNumbers);
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%Stop the timer
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endTime = clock();
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%Print the results
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printf("The sum of all the numbers that can be written as the sum of the fifth powers of their digits is %d\n", sumOfArray)
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printf("It took %f seconds to run this algorithm\n", etime(endTime, startTime))
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end
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%Returns an array with the individual digits of the number passed to it
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function [listOfDigits] = getDigits(num)
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listOfDigits = []; %This array holds the individual digits of num
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%The easiest way to get the individual digits of a number is by converting it to a string
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digits = num2str(num);
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%Start with the first digit, convert it to an integer, store it in the table, and move to the next digit
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for cnt = 1 : size(digits)(2)
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listOfDigits(end + 1) = str2num(substr(digits, cnt, 1));
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end
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end
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%{
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Results:
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The sum of all the numbers that can be written as the sum of the fifth powers of their digits is 443839
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It took 1849.877525 seconds to run this algorithm
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%}
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