Updated all problems to use fstrings and results()

This commit is contained in:
2020-10-30 16:20:39 -04:00
parent ad458278d4
commit 46216a2807
33 changed files with 280 additions and 452 deletions

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@@ -1,11 +1,11 @@
#Project Euler/Python/Problem16.py
#Matthew Ellison
# Created: 02-03-19
#Modified: 03-28-19
#Modified: 10-30-20
#What is the sum of the digits of the number 2^1000?
#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
"""
Copyright (C) 2019 Matthew Ellison
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
@@ -23,7 +23,6 @@
from Problems.Problem import Problem
from Stopwatch import Stopwatch
from Unsolved import Unsolved
@@ -66,6 +65,7 @@ class Problem16(Problem):
#Throw a flag to show the problem is solved
self.solved = True
#Reset the problem so it can be run again
def reset(self):
super().reset()
@@ -73,6 +73,13 @@ class Problem16(Problem):
self.sumOfElements = 0
#Gets
#Returns the result of solving the problem
def getResult(self):
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can see the result")
return f"{self.__numToPower}^{self.__power} = {self.num}\n" \
f"The sum of the elements is {self.sumOfElements}"
#Returns the number that was calculated
def getNumber(self):
#If the problem hasn't been solved throw an exception
@@ -86,15 +93,6 @@ class Problem16(Problem):
raise Unsolved("You must solve the problem before you can get the sum of the digits of the number")
return self.sumOfElements
#If you are running this file, automatically start the correct function
if __name__ == "__main__":
problem = Problem16()
print(problem.getDescription()) #Print the description of the problem
problem.solve() #Solve the problem
#Print the results
print(problem.getResult())
print("It took " + problem.getTime() + " to solve this algorithm")
"""Results:
2^1000 = 10715086071862673209484250490600018105614048117055336074437503883703510511249361224931983788156958581275946729175531468251871452856923140435984577574698574803934567774824230985421074605062371141877954182153046474983581941267398767559165543946077062914571196477686542167660429831652624386837205668069376