#ProjectEuler/Python/Problem27.py #Matthew Ellison # Created: 09-15-19 #Modified: 09-15-19 #Find the product of the coefficients, |a| < 1000 and |b| <= 1000, for the quadratic expression that produces the maximum number of primes for consecutive values of n, starting with n=0. #Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses """ Copyright (C) 2019 Matthew Ellison This program is free software: you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License for more details. You should have received a copy of the GNU Lesser General Public License along with this program. If not, see . """ from Stopwatch import Stopwatch import Algorithms def Problem27(): #Setup the variables topA = 0 #The A for the most n's generated topB = 0 #The B for the most n's generated topN = 0 #The most n's generated primes = Algorithms.getPrimes(12000) #A list of all primes that could possibly be generated with this formula #Start with the lowest possible A and check all possibilities after that for a in range(-999, 999): #Start with the lowest possible B and check all possibilities after that for b in range(-1000, 1000): #Start with n=0 and check the formula to see how many primes you can get get with concecutive n's n = 0 quadratic = (n * n) + (a * n) + b while(quadratic in primes): n += 1 quadratic = (n * n) + (a * n) + b n -= 1 #Negate an n because the last formula failed #Set all the largest numbers if this created more primes than any other if(n > topN): topN = n topB = b topA = a print("The greatest number of primes found is " + str(topN)) print("It was found with A = " + str(topA) + ", B = " + str(topB)) print("The product of A and B is " + str(topA * topB)) #This calls the appropriate functions if the script is called stand alone if __name__ == "__main__": timer = Stopwatch() timer.start() Problem27() timer.stop() print("It took " + timer.getString() + " to run this algorithm") """ Results: The greatest number of primes found is 70 It was found with A = -61, B = 971 The product of A and B is -59231 It took 35.775 seconds to run this algorithm """