#Project Euler/Python/Problem8.py
#Matthew Ellison
# Created: 01-29-19
#Modified: 03-28-19
#Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
"""
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
"""
#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
"""
	Copyright (C) 2019  Matthew Ellison

	This program is free software: you can redistribute it and/or modify
	it under the terms of the GNU Lesser General Public License as published by
	the Free Software Foundation, either version 3 of the License, or
	(at your option) any later version.

	This program is distributed in the hope that it will be useful,
	but WITHOUT ANY WARRANTY; without even the implied warranty of
	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
	GNU Lesser General Public License for more details.

	You should have received a copy of the GNU Lesser General Public License
	along with this program.  If not, see <https://www.gnu.org/licenses/>.
"""


from Stopwatch import Stopwatch

#The number
__number = "7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450"


def Problem8():
	#Setup the variables
	largestProduct = 0	#Holds the largest product of 13 adjacent digits
	largestString = ""	#Holds the 13 adjacent numbers that produce the largest product

	#Start at the 13th entry and multiply all single digit numbers before and including that number together
	numberLocation = 12	#The location in the number that you are working from
	while(numberLocation < len(__number)):
		currentProduct = int(__number[numberLocation]) * int(__number[numberLocation - 1]) * int(__number[numberLocation - 2]) * int(__number[numberLocation - 3]) * int(__number[numberLocation - 4]) * int(__number[numberLocation - 5]) * int(__number[numberLocation - 6]) * int(__number[numberLocation - 7]) * int(__number[numberLocation - 8]) * int(__number[numberLocation - 9]) * int(__number[numberLocation - 10]) * int(__number[numberLocation - 11]) * int(__number[numberLocation - 12])
		#Save the largest product
		if(currentProduct > largestProduct):
			largestProduct = currentProduct
			largestString = __number[numberLocation - 12:numberLocation + 1]	#Have to add one because it stops before the second subscript
		#Move to the next location
		numberLocation += 1

	#Print the results
	print("The largest product of 13 adjacent digits in the number is " + str(largestProduct))
	print("The numbers are: " + largestString)

#If you are running this file, automatically start the correct function
if __name__ == '__main__':
	timer = Stopwatch()	#Determines the algorithm's run time
	timer.start()	#Start the timer
	Problem8()		#Call the function that answers the question
	timer.stop()	#Stop the timer
	print("It took " + timer.getString() + " to run this algorithm")

"""Results:
The largest product of 13 adjacent digits in the number is 23514624000
The numbers are: 5576689664895
It took 2.593 milliseconds to run this algorithm
"""