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163 lines
4.7 KiB
Python
163 lines
4.7 KiB
Python
#ProjectEuler/Python/Problem19.py
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#Matthew Ellison
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# Created: 03-13-19
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#Modified: 03-28-19
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#How many Sundays fell on the first of the month during the twentieth century (1 Jan 1901 to 31 Dec 2000)?
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"""
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You are given the following information, but you may prefer to do some research for yourself.
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1 Jan 1900 was a Monday.
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Thirty days has September,
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April, June and November.
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All the rest have thirty-one,
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Saving February alone,
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Which has twenty-eight, rain or shine.
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And on leap years, twenty-nine.
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A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
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"""
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#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
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"""
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Copyright (C) 2019 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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"""
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from Stopwatch import Stopwatch
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class DAYS:
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SUNDAY = 0
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MONDAY = 1
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TUESDAY = 2
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WEDNESDAY = 3
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THURSDAY = 4
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FRIDAY = 5
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SATURDAY = 6
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NUMBER_OF_DAYS = 7
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ERROR = 8
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START_YEAR = 1901 #The year we start counting sundays
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END_YEAR = 2000 #The year we stop counting sundays
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#Return the day of the week that the date you pass into it is on
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def getDay(month: int, day: int, year: int) -> DAYS:
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#Make sure the numebrs are within propper bounds
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if((month < 1) or (month > 12) or (day < 1) or (day > 31) or (year < 1)):
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return DAYS.ERROR
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numDays = 0 #The number of days between 01-01-0001 and the date given
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currentYear = 1
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currentMonth = 1
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currentDay = DAYS.SATURDAY
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day -= 1
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#Add the correct number of days for every year
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while(currentYear < year):
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if(isLeapYear(currentYear)):
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numDays += 366
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else:
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numDays += 365
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currentYear += 1
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#Add the correct number of days for eveyr month
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while(currentMonth < month):
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#February
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if(currentMonth == 2):
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if(isLeapYear(currentYear)):
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numDays += 29
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else:
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numDays += 28
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elif((currentMonth == 1) or (currentMonth == 3) or (currentMonth == 5) or (currentMonth == 7) or (currentMonth == 8) or (currentMonth == 10) or (currentMonth == 12)):
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numDays += 31
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#For 30 day months
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else:
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numDays += 30
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currentMonth += 1
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#Account for the weird year of 1752
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if(year > 1752):
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numDays -= 11
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elif(year == 1752):
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if(month > 9):
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numDays -= 11
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elif(month == 9):
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if(day >= 14):
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numDays -= 11
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#Days 3-13 were skipped that year
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elif((day > 2) and (day < 14)):
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return DAYS.ERROR
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#Add the correct number of days for every day
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numDays += day
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currentDay += numDays
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currentDay = currentDay % DAYS.NUMBER_OF_DAYS
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if(currentDay == DAYS.SUNDAY):
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return DAYS.SUNDAY
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elif(currentDay == DAYS.MONDAY):
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return DAYS.MONDAY
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elif(currentDay == DAYS.TUESDAY):
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return DAYS.TUESDAY
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elif(currentDay == DAYS.WEDNESDAY):
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return DAYS.WEDNESDAY
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elif(currentDay == DAYS.THURSDAY):
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return DAYS.THURSDAY
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elif(currentDay == DAYS.FRIDAY):
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return DAYS.FRIDAY
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elif(currentDay == DAYS.SATURDAY):
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return DAYS.SATURDAY
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else:
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return DAYS.ERROR
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#Returns true if the year passed to it is a leap year
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def isLeapYear(year: int) -> bool:
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if(year < 1):
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return False
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elif((year % 100) == 0):
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#This rule only applies at and after 1800
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if(year <= 1700):
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return True
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elif((year % 400) == 0):
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return True
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elif((year % 4) == 0):
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return True
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return False
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def Problem19():
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totalSundays = 0 #Keep track of the number of sundays
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#Run for all years from start to end
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for year in range(START_YEAR, END_YEAR + 1):
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#Run for all months in the year
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for month in range(1, 13):
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day = getDay(month, 1, year)
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if(day == DAYS.ERROR):
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print("There was an error with the day")
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return
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elif(day == DAYS.SUNDAY):
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totalSundays += 1
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#Print the results
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print("There are " + str(totalSundays) + " Sundays that landed on the first of the month from " + str(START_YEAR) + " to " + str(END_YEAR))
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#Run automatically if the script was called stand alone
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if __name__ == "__main__":
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timer = Stopwatch()
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timer.start()
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Problem19()
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timer.stop()
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print("It took " + timer.getString() + " to run this algorithm")
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""" Results:
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There are 171 Sundays that landed on the first of the month from 1901 to 2000
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It took 724.930 milliseconds to run this algorithm
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"""
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