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ProjectEulerPython/Problems/Problem14.py

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Python

#ProjectEuler/Python/Problem14.py
#Matthew Ellison
# Created: 01-31-19
#Modified: 07-18-20
"""
The following iterative sequence is defined for the set of positive integers:
n → n/2 (n is even)
n → 3n + 1 (n is odd)
Which starting number, under one million, produces the longest chain?
"""
#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
"""
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>.
"""
from Problems.Problem import Problem
from Stopwatch import Stopwatch
from Unsolved import Unsolved
class Problem14(Problem):
#Variables
__topNum = 1000000 - 1 #The largest number that you will check against the chain
#Functions
#Constructor
def __init__(self):
super().__init__("Which starting number, under one million, produces the longest chain using the itterative sequence?")
self.maxLength = 0
self.maxNum = 0
#Operational functions
#Solve the problem
def solve(self):
#If the problem has already been solved do nothing and end the function
if(self.solved):
return
#Start the timer
self.timer.start()
#Loop through all number <= topNum and check them against the series
for currentNum in range(1, self.__topNum + 1):
currentLength = self.checkSeries(currentNum)
#If the current number has a longer series than the max then the current becomes the max
if(currentLength > self.maxLength):
self.maxLength = currentLength
self.maxNum = currentNum
#Stop the timer
self.timer.stop()
#Save the results
self.result = "The number " + str(self.maxNum) + " produced a chain of " + str(self.maxLength) + " steps"
#Throw a flag to show the problem is solved
self.solved = True
#This function follows the rules of the sequence and returns its length
def checkSeries(self, num: int) -> int:
length = 1 #Start at 1 because you need to count the starting number
#Follow the series, adding 1 for each step you take
while(num > 1):
if((num % 2) == 0):
num = num / 2
else:
num = (3 * num) + 1
length += 1
return length
#Reset the problem so it can be run again
def reset(self):
super().reset()
self.maxLength = 0
self.maxNum = 0
#Gets
#Returns the length of the requested chain
def getLength(self):
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can get the length of the requested chain")
return self.maxLength
#Returns the starting number of the requested chain
def getStartingNumber(self):
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can get the number that started the series")
return self.maxNum
#If you are running this file, automatically start the correct function
if __name__ == "__main__":
problem = Problem14()
print(problem.getDescription()) #Print the description of the problem
problem.solve() #Solve the problem
#Print the results
print(problem.getResult())
print("It took " + problem.getTime() + " to solve this algorithm")
"""Results:
The longest chain with a starting number < 1000000 is 837799 with a length of 525
It took 28.893 seconds to run this algorithm
"""