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127 lines
6.0 KiB
Python
127 lines
6.0 KiB
Python
#Project Euler/Python/Problem8.py
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#Matthew Ellison
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# Created: 01-29-19
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#Modified: 07-18-20
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#Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
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"""
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73167176531330624919225119674426574742355349194934
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96983520312774506326239578318016984801869478851843
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85861560789112949495459501737958331952853208805511
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12540698747158523863050715693290963295227443043557
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66896648950445244523161731856403098711121722383113
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62229893423380308135336276614282806444486645238749
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30358907296290491560440772390713810515859307960866
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70172427121883998797908792274921901699720888093776
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65727333001053367881220235421809751254540594752243
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52584907711670556013604839586446706324415722155397
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53697817977846174064955149290862569321978468622482
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83972241375657056057490261407972968652414535100474
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82166370484403199890008895243450658541227588666881
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16427171479924442928230863465674813919123162824586
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17866458359124566529476545682848912883142607690042
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24219022671055626321111109370544217506941658960408
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07198403850962455444362981230987879927244284909188
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84580156166097919133875499200524063689912560717606
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05886116467109405077541002256983155200055935729725
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71636269561882670428252483600823257530420752963450
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"""
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#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
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"""
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Copyright (C) 2020 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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"""
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from Problems.Problem import Problem
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from Stopwatch import Stopwatch
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from Unsolved import Unsolved
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class Problem8(Problem):
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#Variables
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#The number
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__number = "7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450"
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#Functions
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#Constructor
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def __init__(self):
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super().__init__("Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?")
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self.maxNums = "" #Holds the string of the largest product
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self.maxProduct = 0 #Holds the largest product of 13 numbers
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#Operational functions
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#Solve the problem
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def solve(self):
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#If the problem has already been solved do nothing and end the function
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if(self.solved):
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return
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#Start the timer
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self.timer.start()
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#Start at the 13th entry and multiply all single digit numbers before and including that number together
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cnt = 12 #The location in the number that you are working from
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for cnt in range(12, len(self.__number)):
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currentProduct = int(self.__number[cnt]) * int(self.__number[cnt - 1]) * int(self.__number[cnt - 2]) * int(self.__number[cnt - 3]) * int(self.__number[cnt - 4]) * int(self.__number[cnt - 5]) * int(self.__number[cnt - 6]) * int(self.__number[cnt - 7]) * int(self.__number[cnt - 8]) * int(self.__number[cnt - 9]) * int(self.__number[cnt - 10]) * int(self.__number[cnt - 11]) * int(self.__number[cnt - 12])
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#Save the largest product
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if(currentProduct > self.maxProduct):
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self.maxProduct = currentProduct
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self.maxNums = self.__number[cnt - 12:cnt + 1] #Have to add one because it stops before the second subscript
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#Move to the next location
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cnt += 1
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#Stop the timer
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self.timer.stop
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#Save the results
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self.result = "The largest product of 13 adjacent digits in the number is " + str(self.maxProduct) + "\nThe numbers are: " + self.maxNums
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#Throw a flag to show the problem is solved
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self.solved = True
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#Reset the problem so it can be run again
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def reset(self):
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super().reset()
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maxNums = ""
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maxProduct = 0
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#Gets
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#Returns the string of number that produces the largest product
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def getLargestNums(self) -> str:
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#If the problem hasn't been solved throw an exception
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if(not self.solved):
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raise Unsolved("You must solve the problem before you can get the nums the produce the largest product")
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return self.maxNums
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#Returns the requested product
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def getLargestProduct(self) -> int:
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#If the problem hasn't been solved throw an exception
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if(not self.solved):
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raise Unsolved("You must solve the problem before you can get the requested product")
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return self.maxProduct
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#If you are running this file, automatically start the correct function
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if __name__ == '__main__':
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problem = Problem8()
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print(problem.getDescription()) #Print the description of the problem
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problem.solve() #Solve the problem
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#Print the results
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print(problem.getResult())
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print("It took " + problem.getTime() + " to solve this algorithm")
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"""Results:
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The largest product of 13 adjacent digits in the number is 23514624000
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The numbers are: 5576689664895
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It took 2.593 milliseconds to run this algorithm
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"""
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