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ProjectEulerPython/Problems/Problem9.py

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Python

#Project Euler/Python/Problem9.py
#Matthew Ellison
# Created: 01-29-19
#Modified: 07-18-20
#There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.
#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
"""
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>.
"""
from Problems.Problem import Problem
from Stopwatch import Stopwatch
from Unsolved import Unsolved
import math
class Problem9(Problem):
#Functions
#Constructor
def __init__(self):
super().__init__("There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.")
self.a = 1
self.b = 0
self.c = 0
self.found = False
#Operational functions
#Solve the problem
def solve(self):
#If the problem has already been solved do nothing and end the function
if(self.solved):
return
#Start the timer
self.timer.start()
#Start with the lowest possible a , 1, and search for the b and c to complete the triplet
while((self.a <= (1000 / 3)) and (not self.found)):
#Setup b and c
self.b = self.a + 1 #b must be > a to be a triplet
self.c = math.hypot(self.a, self.b) #C is the hyp
#Loop through possible b's and calculate c's until you find the numbers or the sum gets too large
while((self.a + self.b + self.c) < 1000):
self.b += 1
self.c = math.hypot(self.a, self.b)
#If c is an integer make it one
if((self.c % 1) == 0):
self.c = int(round(self.c))
#Check if the correct sides were found
if((self.a + self.b + self.c) == 1000):
self.found = True
#Otherwise increment a to the next possible number
else:
self.a += 1
#Stop the timer
self.timer.stop()
#Save the results
if(self.found):
self.result = "The Pythagorean triplet where a + b + c = 1000 is " + str(self.a) + " " + str(self.b) + " " + str(int(self.c)) + "\nThe product of those numbers is " + str(int(self.a * self.b * self.c))
else:
self.result = "Could not find the triplet where a + b + c = 1000"
#Throw a flag to show the problem is solved
self.solved = True
#Reset the problem so it can be run again
def reset(self):
super().reset()
self.a = 1
self.b = 0
self.c = 0
found = False
#Gets
#Returns the length of the first side
def getSideA(self) -> int:
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can get the length of the first side")
return self.a
#Returns the length of the second side
def getSideB(self) -> int:
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can get the length of the second side")
return self.b
#Returns the length of the hyp
def getSideC(self) -> float:
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can get the length of the hyp")
return self.c
#Returns the product of the 3 sides
def getProduct(self) -> int:
#If the problem hasn't been solved throw an exception
if(not self.solved):
raise Unsolved("You must solve the problem before you can get the length first side")
return int(self.a * self.b * self.c)
#If you are running this file, automatically start the correct function
if __name__ == "__main__":
problem = Problem9()
print(problem.getDescription()) #Print the description of the problem
problem.solve() #Solve the problem
#Print the results
print(problem.getResult())
print("It took " + problem.getTime() + " to solve this algorithm")
"""Results:
The Pythagorean triplet where a + b + c = 1000 is 200 375 425
The product of those numbers is 31875000
It took 22.106 milliseconds to run this algorithm
"""