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129 lines
4.4 KiB
Python
129 lines
4.4 KiB
Python
#Project Euler/Python/Problem9.py
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#Matthew Ellison
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# Created: 01-29-19
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#Modified: 07-18-20
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#There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.
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#Unless otherwise listed, all of my non-standard imports can be gotten from my pyClasses repository at https://bitbucket.org/Mattrixwv/pyClasses
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"""
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Copyright (C) 2020 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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"""
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from Problems.Problem import Problem
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from Stopwatch import Stopwatch
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from Unsolved import Unsolved
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import math
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class Problem9(Problem):
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#Functions
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#Constructor
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def __init__(self):
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super().__init__("There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.")
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self.a = 1
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self.b = 0
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self.c = 0
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self.found = False
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#Operational functions
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#Solve the problem
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def solve(self):
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#If the problem has already been solved do nothing and end the function
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if(self.solved):
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return
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#Start the timer
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self.timer.start()
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#Start with the lowest possible a , 1, and search for the b and c to complete the triplet
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while((self.a <= (1000 / 3)) and (not self.found)):
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#Setup b and c
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self.b = self.a + 1 #b must be > a to be a triplet
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self.c = math.hypot(self.a, self.b) #C is the hyp
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#Loop through possible b's and calculate c's until you find the numbers or the sum gets too large
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while((self.a + self.b + self.c) < 1000):
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self.b += 1
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self.c = math.hypot(self.a, self.b)
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#If c is an integer make it one
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if((self.c % 1) == 0):
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self.c = int(round(self.c))
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#Check if the correct sides were found
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if((self.a + self.b + self.c) == 1000):
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self.found = True
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#Otherwise increment a to the next possible number
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else:
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self.a += 1
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#Stop the timer
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self.timer.stop()
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#Save the results
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if(self.found):
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self.result = "The Pythagorean triplet where a + b + c = 1000 is " + str(self.a) + " " + str(self.b) + " " + str(int(self.c)) + "\nThe product of those numbers is " + str(int(self.a * self.b * self.c))
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else:
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self.result = "Could not find the triplet where a + b + c = 1000"
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#Throw a flag to show the problem is solved
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self.solved = True
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#Reset the problem so it can be run again
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def reset(self):
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super().reset()
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self.a = 1
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self.b = 0
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self.c = 0
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found = False
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#Gets
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#Returns the length of the first side
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def getSideA(self) -> int:
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#If the problem hasn't been solved throw an exception
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if(not self.solved):
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raise Unsolved("You must solve the problem before you can get the length of the first side")
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return self.a
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#Returns the length of the second side
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def getSideB(self) -> int:
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#If the problem hasn't been solved throw an exception
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if(not self.solved):
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raise Unsolved("You must solve the problem before you can get the length of the second side")
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return self.b
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#Returns the length of the hyp
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def getSideC(self) -> float:
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#If the problem hasn't been solved throw an exception
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if(not self.solved):
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raise Unsolved("You must solve the problem before you can get the length of the hyp")
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return self.c
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#Returns the product of the 3 sides
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def getProduct(self) -> int:
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#If the problem hasn't been solved throw an exception
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if(not self.solved):
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raise Unsolved("You must solve the problem before you can get the length first side")
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return int(self.a * self.b * self.c)
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#If you are running this file, automatically start the correct function
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if __name__ == "__main__":
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problem = Problem9()
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print(problem.getDescription()) #Print the description of the problem
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problem.solve() #Solve the problem
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#Print the results
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print(problem.getResult())
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print("It took " + problem.getTime() + " to solve this algorithm")
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"""Results:
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The Pythagorean triplet where a + b + c = 1000 is 200 375 425
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The product of those numbers is 31875000
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It took 22.106 milliseconds to run this algorithm
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"""
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