Added solution for problem 35

src/Problems.rs

@@ -57,14 +57,15 @@ pub mod Problem31;
 pub mod Problem32;
 pub mod Problem33;
 pub mod Problem34;
+pub mod Problem35;
 pub mod Problem67;
 
 
-pub static problemNumbers: [u32; 36] = [ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9,
+pub static problemNumbers: [u32; 37] = [ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9,
 									10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
 									20, 21, 22, 23, 24, 25, 26, 27, 28, 29,
-									30, 31, 32, 33, 34, 67];
-pub static tooLong: [u32; 7] = [3, 5, 15, 23, 24, 25, 27];
+									30, 31, 32, 33, 34, 35, 67];
+pub static tooLong: [u32; 8] = [3, 5, 15, 23, 24, 25, 27, 35];
 
 pub fn solveProblem(problemNumber: u32, description: bool, solve: bool) -> Answer::Answer{
 	let mut answer = Answer::Answer::new("".to_string(), "".to_string(), 0);
@@ -344,6 +345,14 @@ pub fn solveProblem(problemNumber: u32, description: bool, solve: bool) -> Answe
 			answer = Problem34::solve();
 		}
 	}
+	else if(problemNumber == 35){
+		if(description){
+			println!("{}", Problem35::getDescription());
+		}
+		if(solve){
+			answer = Problem35::solve();
+		}
+	}
 	else if(problemNumber == 67){
 		if(description){
 			println!("{}", Problem67::getDescription());

src/Problems/Problem35.rs

@@ -0,0 +1,88 @@
+//ProjectEulerRust/src/Problems/Problem35.rs
+//Matthew Ellison
+// Created: 06-06-21
+//Modified: 06-06-21
+//How many circular primes are there below one million?
+//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/RustClasses
+/*
+	Copyright (C) 2021  Matthew Ellison
+
+	This program is free software: you can redistribute it and/or modify
+	it under the terms of the GNU Lesser General Public License as published by
+	the Free Software Foundation, either version 3 of the License, or
+	(at your option) any later version.
+
+	This program is distributed in the hope that it will be useful,
+	but WITHOUT ANY WARRANTY; without even the implied warranty of
+	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+	GNU Lesser General Public License for more details.
+
+	You should have received a copy of the GNU Lesser General Public License
+	along with this program.  If not, see <https://www.gnu.org/licenses/>.
+*/
+
+
+extern crate myClasses;
+use crate::Problems::Answer::Answer;
+
+pub fn getDescription() -> String{
+	"How many circular primes are there below one million?".to_string()
+}
+
+pub fn solve() -> Answer{
+	//Variables
+	//Static variables
+	let maxNum = 999999;	//The largest number that we are checking for primes
+	//Instance variables
+	let mut circularPrimes = Vec::<i64>::new();
+
+	//Start the timer
+	let mut timer = myClasses::Stopwatch::Stopwatch::new();
+	timer.start();
+
+	//Get all primes under 1,000,000
+	let primes = myClasses::Algorithms::getPrimes(maxNum);
+	//Go through all primes, get all their rotations, and check if those numbers are also primes
+	for num in &primes{
+		let prime = *num;
+		let mut allRotationsPrime = true;
+		//Get all of the rotations of the prime and see if they are also prime
+		let rotations = getRotations(&prime.to_string());
+		for rotation in rotations{
+			let p = rotation.parse::<i64>().unwrap();
+			if(!primes.contains(&p)){
+				allRotationsPrime = false;
+				break;
+			}
+		}
+		//If all rotations are prime add it to the list of circular primes
+		if(allRotationsPrime){
+			circularPrimes.push(prime);
+		}
+	}
+
+	//Stop the timer
+	timer.stop();
+
+	return Answer::new(format!("The number of all circular prime numbers under {} is {}", maxNum, circularPrimes.len()), timer.getString(), timer.getNano());
+}
+
+fn getRotations(par1: &String) -> Vec::<String>{
+	let mut string = String::from(par1);
+	let stringCount = String::from(par1).chars().count();
+	let mut rotations = Vec::<String>::new();
+	rotations.push(string.to_string());
+	for _cnt in 1 as usize .. stringCount{
+		let mut tempString = string[1..].to_string();
+		let tempString2 = string[..1].to_owned();
+		tempString.push_str(&tempString2);
+		string = String::from(tempString);
+		rotations.push(string.to_string());
+	}
+	return rotations;
+}
+
+/* Results:
+The number of all circular prime numbers under 999999 is 55
+It took an average of 3.576 seconds to run this problem through 100 iterations
+*/