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138 lines
4.4 KiB
TypeScript
138 lines
4.4 KiB
TypeScript
//ProjectEulerTS/Problems/Problem21.ts
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//Matthew Ellison
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// Created: 04-08-21
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//Modified: 07-14-21
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//Evaluate the sum of all the amicable numbers under 10000
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//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/typescriptClasses
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/*
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Copyright (C) 2021 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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*/
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import { getSum } from "../../../Typescript/typescriptClasses/ArrayAlgorithms";
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import { getDivisors } from "../../../Typescript/typescriptClasses/NumberAlgorithms";
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import { Problem } from "./Problem";
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export class Problem21 extends Problem{
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//Variables
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//Static variables
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private static LIMIT: number = 10000; //The number that is > the largest number to be checked
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//Instance variables
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private divisorSum: number[]; //Holds the sum of the divisors of the subscript number
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private amicable: number[]; //Holds all amicable numbers
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//Functions
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//Constructor
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public constructor(){
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super(`Evaluate the sum of all the amicable numbers under ${Problem21.LIMIT}`);
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this.divisorSum = [];
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this.amicable = [];
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this.reserveArray();
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}
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//Operational functions
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//Reserve the size of the array to speed up insertion
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private reserveArray(): void{
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//Reserving it now makes it faster later
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//Make sure the array is filled with 0's
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while(this.divisorSum.length < Problem21.LIMIT){
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this.divisorSum.push(0);
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}
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}
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//Solve the problem
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public solve(): void{
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//If the problem has already been solved do nothing and end the function
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if(this.solved){
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return;
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}
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//Start the timer
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this.timer.start();
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//Generate the divisors of all numbers < 10000, get their sum, and add it to the list
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for(let cnt = 1;cnt < Problem21.LIMIT;++cnt){
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let divisors: number[] = getDivisors(cnt); //Get all the divisors of a number
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if(divisors.length > 1){
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divisors.pop(); //Remove the last element because it will be the number itself
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}
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this.divisorSum[cnt] = getSum(divisors);
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}
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//Check every sum of divisors in the list for matching sum
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for(let cnt = 1;cnt < this.divisorSum.length;++cnt){
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let sum: number = this.divisorSum[cnt];
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//If the sum is greater than the number of divisors then it is impossible to be amicable. Skip the number and continue
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if(sum >= this.divisorSum.length){
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continue;
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}
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//We know that divisorSum[cnt] == sum, so if divisorSum[sum] == cnt we found an amicable number
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if(this.divisorSum[sum] == cnt){
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//A number can't be amicable with itself
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if(sum == cnt){
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continue;
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}
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//Add it to the array of amicable numbers
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this.amicable.push(cnt);
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}
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}
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//Sort the array for neatness
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this.amicable.sort((n1, n2) => n1 - n2);
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//Stop the timer
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this.timer.stop();
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//Throw a flag to show the problem is solved
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this.solved = true;
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}
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//Reset the problem so it can be run again
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public reset(): void{
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super.reset();
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this.divisorSum = [];
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this.amicable = [];
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this.reserveArray();
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}
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//Gets
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//Returns the result of solving the problem
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public getResult(): string{
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this.solvedCheck("result");
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let result: string = `All amicable numbers less than ${Problem21.LIMIT} are\n`;
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for(let cnt = 0;cnt < this.amicable.length;++cnt){
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result += `${this.amicable[cnt]}\n`;
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}
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result += `The sum of all of these amicable numbers is ${getSum(this.amicable)}`;
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return result;
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}
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//Returns a vector with all of the amicable numbers calculated
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public getAmicable(): number[]{
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this.solvedCheck("amicable numbers");
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return this.amicable;
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}
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//Returns the sum of all of the amicable numbers
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public getSum(): number{
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this.solvedCheck("sum of the amicable numbers");
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return getSum(this.amicable);
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}
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}
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/* Results:
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The sum of all of these amicable numbers is 31626
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It took an average of 7.454 milliseconds to run this problem through 100 iterations
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*/
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