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Source/Problem14.cpp

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+//ProjectEuler/C++/Source/Problem14.cpp
+//Matthew Ellison
+// Created: 09-29-18
+//Modified: 07-14-19
+/*
+The following iterative sequence is defined for the set of positive integers:
+n → n/2 (n is even)
+n → 3n + 1 (n is odd)
+Which starting number, under one million, produces the longest chain?
+*/
+//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/myClasses
+/*
+	Copyright (C) 2019  Matthew Ellison
+
+	This program is free software: you can redistribute it and/or modify
+	it under the terms of the GNU Lesser General Public License as published by
+	the Free Software Foundation, either version 3 of the License, or
+	(at your option) any later version.
+
+	This program is distributed in the hope that it will be useful,
+	but WITHOUT ANY WARRANTY; without even the implied warranty of
+	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+	GNU Lesser General Public License for more details.
+
+	You should have received a copy of the GNU Lesser General Public License
+	along with this program.  If not, see <https://www.gnu.org/licenses/>.
+*/
+
+
+#include <cinttypes>
+#include <string>
+#include <sstream>
+#include "Stopwatch.hpp"
+#include "../Headers/Problem.hpp"
+#include "../Headers/Problem14.hpp"
+
+
+uint64_t Problem14::MAX_NUM = 1000000;
+
+uint64_t Problem14::checkSeries(uint64_t num){
+	uint64_t length = 1;	//Start at 1 because you need to count the starting number
+
+	//Follow the series, adding 1 for each step you take
+	while(num > 1){
+		if((num % 2) == 0){
+			num /= 2;
+		}
+		else{
+			num = (3 * num) + 1;
+		}
+		++length;
+	}
+	return length;
+}
+
+Problem14::Problem14() : Problem("Which starting number, under one million, produces the longest chain using the itterative sequence?"), maxLength(0), maxNum(0){
+
+}
+
+void Problem14::solve(){
+	//If the problem has already been solved do nothing and end the function
+	if(solved){
+		return;
+	}
+
+	//Start the timer
+	timer.start();
+
+	//Loop through all numbers less than 1000000 and check them agains the series
+	for(uint64_t currentNum = 1;currentNum < MAX_NUM;++currentNum){
+		uint64_t currentLength = checkSeries(currentNum);
+		//If the current number has a longer series than the max then the current becomes the max
+		if(currentLength > maxLength){
+			maxLength = currentLength;
+			maxNum = currentNum;
+		}
+	}
+
+	//Stop the timer
+	timer.stop();
+
+	//Throw a flag to show the problem is solved
+	solved = true;
+}
+
+std::string Problem14::getString() const{
+	//If the problem hasn't been solved throw an exception
+	if(!solved){
+		throw unsolved();
+	}
+
+	std::stringstream results;
+	results << "The number " << maxNum << " produced a chain of " << maxLength << " steps";
+	return results.str();
+}
+
+uint64_t Problem14::getLength() const{
+	//If the problem hasn't been solved throw an exception
+	if(!solved){
+		throw unsolved();
+	}
+	return maxLength;
+}
+
+uint64_t Problem14::getStartingNumber() const{
+	//If the problem hasn't been solved throw an exception
+	if(!solved){
+		throw unsolved();
+	}
+	return maxNum;
+}