Added solution to problem 26

This commit is contained in:
2020-09-11 13:09:52 -04:00
parent e52e39b6e4
commit 450524fcc1
2 changed files with 135 additions and 1 deletions

View File

@@ -32,7 +32,7 @@ namespace ProjectEulerCS{
private static readonly List<int> _PROBLEM_NUMBERS = new List<int>()
{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
20, 21, 22, 23, 24, 25, 67};
20, 21, 22, 23, 24, 25, 26, 67};
public static System.Collections.Generic.List<int> PROBLEM_NUMBERS{
get { return _PROBLEM_NUMBERS; }
}
@@ -66,6 +66,7 @@ namespace ProjectEulerCS{
case 23: problem = new Problem23(); break;
case 24: problem = new Problem24(); break;
case 25: problem = new Problem25(); break;
case 26: problem = new Problem26(); break;
case 67: problem = new Problem67(); break;
}
return problem;

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@@ -0,0 +1,133 @@
//ProjectEuler/ProjectEulerCS/src/Problems/Problem26.cs
//Matthew Ellison
// Created: 09-11-20
//Modified: 09-11-20
//What is the index of the first term in the Fibonacci sequence to contain 1000 digits?
//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/CSClasses
/*
Copyright (C) 2020 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>.
*/
using System.Collections.Generic;
namespace ProjectEulerCS.Problems{
public class Problem26 : Problem{
//Variables
//Static variables
private const int TOP_NUM = 999; //The number of digits needed in the number
//Instance variables
private int longestCycle; //The length of the longest cycle
private int longestNumber; //The starting denominator of the longest cycle
public int LongestCycle{
get{
if(!solved){
throw new Unsolved();
}
return longestCycle;
}
}
public int LongestNumber{
get{
if(!solved){
throw new Unsolved();
}
return longestNumber;
}
}
public override string Result{
get{
if(!solved){
throw new Unsolved();
}
return $"The longest cycle is {longestCycle} digits long\nIt started with the number {longestNumber}";
}
}
//Functions
//Constructor
public Problem26() : base($"Find the value of d <= {TOP_NUM} for which 1/d contains the longest recurring cycle in its decimal fraction part."){
longestCycle = 0;
longestNumber = 0;
}
//Operational functions
//Solve the problem
public override void Solve(){
//If the problem has already been solved do nothing and end the function
if(solved){
return;
}
//Start the timer
timer.Start();
//Start with 1/2 and find out how long the longest cycle is by checking the remainders
//Loop through every number from 2-999 and use it for the denominator
for(int denominator = 2;denominator <= TOP_NUM;++denominator){
List<int> denomList = new List<int>();
bool endFound = false; //A flag for when we have found an end to the number (either a cycle or a 0 for remainder)
bool cycleFound = false; //A flag to indicate a cycle was detected
int numerator = 1; //The numerator that will be divided. Always starts at 1
while(!endFound){
//Get the remainder after the division
int remainder = numerator % denominator;
//Check if the remainder is 0 and set the flag
if(remainder == 0){
endFound = true;
}
//Check if the remainder is in the list and set the appropriate flags
else if(denomList.Contains(remainder)){
endFound = true;
cycleFound = true;
}
//Else add it to the list
else{
denomList.Add(remainder);
}
//Multiply the remainder by 10 to continue finding the next remainder
numerator = remainder * 10;
}
//If a cycle was found check the size of the list against the largest cycle
if(cycleFound){
//If it is larger than the largest, set it as the new largest
if(denomList.Count > longestCycle){
longestCycle = denomList.Count;
longestNumber = denominator;
}
}
}
//Stop the timer
timer.Stop();
//Throw a flag to show the problem is solved
solved = true;
}
//Reset the problem so it can be run again
public override void Reset(){
base.Reset();
longestCycle = 0;
longestNumber = 1;
}
}
}
/* Results:
The longest cycle is 982 digits long
It started with the number 983
It took an average of 4.657 milliseconds to run this problem through 100 iterations
*/