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--ProjectEuler/lua/Problem15.lua
--Matthew Ellison
-- Created: 02-07-19
--Modified: 03-28-19
--How many routes from the top left corner to the bottom right corner are there through a 20×20 grid if you can only move right and down?
--All of my requires, unless otherwise listed, can be found at https://bitbucket.org/Mattrixwv/luaClasses
--[[
Copyright (C) 2019 Matthew Ellison
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>.
]]
require "Stopwatch"
timer = Stopwatch:create();
timer:start();
GRID_WIDTH = 20;
GRID_HEIGHT = 20;
lowestXReached = 20;
function movement(currentX, currentY)
--Return 1 if you are at the finish location
if((currentX == GRID_WIDTH) and (currentY == GRID_HEIGHT)) then
return 1;
end
local numberMoves = 0;
--Otherwise move one right if you can and recurse
if(currentX < GRID_WIDTH) then
numberMoves = numberMoves + movement(currentX + 1, currentY);
end
--Then move one down and recurse
if(currentY < GRID_HEIGHT) then
numberMoves = numberMoves + movement(currentX, currentY + 1);
end
---Helps keep track of where it is for timing purposes
if(currentX < lowestXReached) then
lowestXReached = currentX;
print("X hit");
print("NumberMoves = " .. numberMoves);
print("position = " .. currentX .. "; " .. currentY);
end
return numberMoves; --Return the number of moves that have been found so far
end
--Start the recursion at the correct location and catch what is returned
numberMoves = movement(0, 0);
timer:stop();
--Print the results
print("The number of paths from 1 corner of a " .. GRID_WIDTH .. " x " .. GRID_HEIGHT .. " grid to the opposite corner is " .. numberMoves);
print("It took " .. timer:getMinutes() .. " seconds to run this algorithm");
--[[Results:
Did not run this program to completion. It ran for 12.5 hours and was over half way done, but I got tired of waiting.
It is coded the same way as the C++ version so should come up to the same answer.
There has got to be a better way to do this problem.
]]