Initial commit with existing files

Problem5.lua

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+--ProjectEuler/lua/Problem5.lua
+--Matthew Ellison
+-- Created: 02-05-19
+--Modified: 03-28-19
+--What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
+--All of my requires, unless otherwise listed, can be found at https://bitbucket.org/Mattrixwv/luaClasses
+--[[
+	Copyright (C) 2019  Matthew Ellison
+
+	This program is free software: you can redistribute it and/or modify
+	it under the terms of the GNU Lesser General Public License as published by
+	the Free Software Foundation, either version 3 of the License, or
+	(at your option) any later version.
+
+	This program is distributed in the hope that it will be useful,
+	but WITHOUT ANY WARRANTY; without even the implied warranty of
+	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+	GNU Lesser General Public License for more details.
+
+	You should have received a copy of the GNU Lesser General Public License
+	along with this program.  If not, see <https://www.gnu.org/licenses/>.
+]]
+
+
+require "Stopwatch"
+
+
+timer = Stopwatch:create();
+timer:start();
+
+--Setup the variables you need
+numFound = false;
+currentNum = 22;	--Start looking at 22 becuase it must be divisible by 2 and greater than 20
+--Start a loop looking for the correct number
+while((not numFound) and (currentNum > 0)) do
+	--Set that you found the number to true because you set this flag when you don't find it
+	numFound = true;
+	--See if the current number is divisible by all number from 1 to 20
+	for divisor=1,20 do
+		--If it is not set a flag to move to the next possible number
+		if((currentNum % divisor) ~= 0) then
+			numFound = false;
+			break;
+		end
+	end
+
+	--Increment the number by 2 to check the next one if you didn't find the number
+	if(not numFound) then
+		currentNum = currentNum + 2
+	end
+end
+
+timer:stop();
+
+--Print the results
+if(currentNum < 0) then
+	print("There was an error: Could not find a number that fit the criteria");
+else
+	print("The smallest positive number that is evenly divisible by all numbers 1-20 is " .. currentNum);
+	print("It took " .. timer:getSeconds() .. " seconds to run this algorithm")
+end
+
+--[[Results:
+The smallest positive number that is evenly divisible by all numbers 1-20 is 232792560
+It took 24.788324 seconds to run this algorithm
+]]