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Created solution to problem32
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109
Problem32.m
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109
Problem32.m
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function [] = Problem32()
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%ProjectEuler/Octave/Problem32.m
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%Matthew Ellison
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% Created: 07-28-20
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%Modified: 07-28-20
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%Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital.
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%{
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Copyright (C) 2020 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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%}
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%Start the timer
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startTime = clock();
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%Setup the variables
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topMultiplicand = 99; %The largest multiplicand to check
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topMultiplier = 4999; %The largest multiplier to check
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listOfProducts = {}; %The list of unique products that are 1-9 pandigital
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sumOfPandigitals = 0; %The sum of the products of the pandigital numbers
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%Create the multiplicand and start working your way up
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for multiplicand = 1 : topMultiplicand
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%Run through all possible multipliers
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for multiplier = multiplicand : topMultiplier
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currentProductSet = [multiplicand, multiplier];
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%If the product is too long move on to the next possible number
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if(size(num2str(getNumString(currentProductSet)))(2) > 9)
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break
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end
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%If the current number is a pandigital that doesn't already exist in the list add it
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if(isPandigital(currentProductSet))
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if(~productInTable(listOfProducts, currentProductSet))
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listOfProducts(end + 1) = currentProductSet;
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end
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end
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end
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end
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%Get the sum of the products of the pandigitals
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for prod = 1 : size(listOfProducts)(2)
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sumOfPandigitals += getProduct(listOfProducts{prod});
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end
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%Stop the timer
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endTime = clock();
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%Print the results
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printf("There are %d unique 1-9 pandigitals\n", size(listOfProducts)(2))
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printf("The sum of the products of these pandigitals is %d\n", sumOfPandigitals)
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printf("It took %f seconds to run this algorithm\n", etime(endTime, startTime))
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end
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function [isPan] = isPandigital(currentSet)
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%Get the number out of the object and put them into a string
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numberString = getNumString(currentSet);
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%Make sure the string is the correct length
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if(size(numberString)(2) != 9)
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isPan = false;
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return;
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end
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%Make sure there is exactly one of this number contained in the string
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for panNumber = 1 : 9
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if(size(strfind(numberString, num2str(panNumber)))(2) != 1)
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isPan = false;
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return;
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end
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end
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isPan = true;
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end
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function [prod] = getProduct(currentSet)
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prod = (currentSet(1) * currentSet(2));
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end
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function [numString] = getNumString(currentSet)
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numString = strcat(num2str(currentSet(1)), num2str(currentSet(2)), num2str(currentSet(1) * currentSet(2)));
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end
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function [inTable] = productInTable(startTable, element)
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inTable = false;
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for cnt = 1 : size(startTable)(2)
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if(getProduct(startTable{cnt}) == getProduct(element))
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inTable = true;
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return;
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end
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end
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end
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%{
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Results:
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There are 7 unique 1-9 pandigitals
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The sum of the products of these pandigitals is 45228
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It took 174.908974 seconds to run this algorithm
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%}
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