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Added solution to problem 31
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@@ -53,4 +53,5 @@ pub mod Problem27;
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pub mod Problem28;
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pub mod Problem29;
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pub mod Problem30;
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pub mod Problem31;
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pub mod Problem67;
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66
src/Problems/Problem31.rs
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66
src/Problems/Problem31.rs
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@@ -0,0 +1,66 @@
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//ProjectEulerRust/src/Problems/Problems31.rs
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//Matthew Ellison
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// Created: 06-19-20
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//Modified: 06-19-20
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//How many different ways can £2 be made using any number of coins?
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//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/RustClasses
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/*
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Copyright (C) 2020 Matthew Ellison
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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*/
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extern crate myClasses;
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use crate::Problems::Answer::Answer;
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pub fn getDescription() -> String{
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"Find the sum of all the numbers that can be written as the sum of the fifth powers of their digits.".to_string()
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}
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pub fn solve() -> Answer{
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let desiredValue = 200;
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let mut permutations = 0;
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//Start the timer
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let mut timer = myClasses::Stopwatch::Stopwatch::new();
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timer.start();
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//Start with 200p and remove the necessary coins with each loop
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for pound2 in (0..=desiredValue).rev().step_by(200){
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for pound1 in (0..=pound2).rev().step_by(100){
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for pence50 in (0..=pound1).rev().step_by(50){
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for pence20 in (0..=pence50).rev().step_by(20){
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for pence10 in (0..=pence20).rev().step_by(10){
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for pence5 in (0..=pence10).rev().step_by(5){
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for _pence2 in (0..=pence5).rev().step_by(2){
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permutations += 1;
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}
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}
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}
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}
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}
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}
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}
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//Stop the timer
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timer.stop();
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return Answer::new(format!("There are {} ways to make 2 pounds with the given denominations of coins", permutations), timer.getString());
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}
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/* Results:
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There are 73682 ways to make 2 pounds with the given denominations of coins
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It took 109.300 microseconds to solve this problem
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*/
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11
src/main.rs
11
src/main.rs
@@ -33,10 +33,10 @@ mod Problems;
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#[derive(PartialEq)]
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enum Selections{EMPTY, SOLVE, DESCRIPTION, LIST, EXIT, SIZE}
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static problemNumbers: [u32; 32] = [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
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static problemNumbers: [u32; 33] = [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
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10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
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20, 21, 22, 23, 24, 25, 26, 27, 28, 29,
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30, 67];
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30, 31, 67];
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fn main(){
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let mut selection = Selections::EMPTY;
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@@ -253,6 +253,10 @@ fn solveProblem(problemNumber: u32){
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println!("{}", Problems::Problem30::getDescription());
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println!("{}", Problems::Problem30::solve());
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}
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else if(problemNumber == 31){
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println!("{}", Problems::Problem31::getDescription());
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println!("{}", Problems::Problem31::solve());
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}
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else if(problemNumber == 67){
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println!("{}", Problems::Problem67::getDescription());
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println!("{}", Problems::Problem67::solve());
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@@ -372,6 +376,9 @@ fn printDescription(problemNumber: u32){
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else if(problemNumber == 30){
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println!("{}", Problems::Problem30::getDescription());
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}
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else if(problemNumber == 31){
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println!("{}", Problems::Problem31::getDescription());
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}
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else if(problemNumber == 67){
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println!("{}", Problems::Problem67::getDescription());
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}
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