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Updated problem 1 algorithm
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@@ -1,7 +1,7 @@
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//ProjectEulerTS/Problems/Problem1.ts
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//Matthew Ellison
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// Created: 10-18-20
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//Modified: 10-18-20
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//Modified: 10-26-20
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//What is the sum of all the multiples of 3 or 5 that are less than 1000
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//Unless otherwise listed all non-standard includes are my own creation and available from https://bibucket.org/Mattrixwv/typescriptClasses
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/*
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@@ -48,14 +48,8 @@ export class Problem1 extends Problem{
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//Start the timer
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this.timer.start();
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for(var num: number = 1;num < 1000;++num){
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if((num % 3) == 0){
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this.fullSum += num;
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}
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else if((num % 5) == 0){
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this.fullSum += num;
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}
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}
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//Get the sum of the progressions of 3 and 5 and remove the sum of progressions of the overlap
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this.fullSum = this.sumOfProgression(3) + this.sumOfProgression(5) - this.sumOfProgression(3 * 5);
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//Stop the timer
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this.timer.stop();
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@@ -68,6 +62,12 @@ export class Problem1 extends Problem{
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super.reset();
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this.fullSum = 0;
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}
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//Gets the sum of the progression of the multiple
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private sumOfProgression(multiple: number): number{
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let numTerms = Math.floor(Problem1.TOP_NUM / multiple); //Get the sum of the progressions of 3 and 5 and remove the sum of progressions of the overlap
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//The sum of progression formula is (n / 2)(a + l). n = number of terms, a = multiple, l = last term
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return ((numTerms / 2) * (multiple + (numTerms * multiple)))
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}
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//Gets
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//Returns the result of solving the problem
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public getResult(): string{
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@@ -86,5 +86,6 @@ export class Problem1 extends Problem{
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}
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/* Results:
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The sum of all numbers < 1000 is 233168
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It took an average of 1.921 microseconds to run this problem through 100 iterations
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*/
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